Computational Questions — Crop Science Reviewer Questions

700 board-style Computational Questions items for the Agriculturist Licensure Examination. Try 30 questions free; lifetime access is ₱49. Biotechnology and current-news items reward recognition rather than derivation. Work them in short, frequent sittings and keep the longer sessions for physiology.

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Board-style items taken from the Crop Science bank. Every answer is explained, which is the part that makes a review question worth doing twice.

Use HSD=q√(MSE/r), q=4.0, MSE=9, r=4. Calculate Tukey HSD.
- A. 6.000 trait units correct
- B. 7.200 trait units
- C. 4.800 trait units
- D. 4.200 trait units
Why: HSD=4.0√(9/4)=6.000.
Compute both quantities in order. First: Output energy is 75000 MJ/ha and input energy is 30000 MJ/ha. Calculate energy input-output ratio. Second: Output is 8000 units and the relevant input is 150 units. Calculate energy productivity as output ÷ input. Which option gives the two computed results, respectively?
- A. 2.250 ; 53.33 units/unit
- B. 2.500 ; 53.33 units/unit correct
- C. 2.500 ; 69.33 units/unit
- D. 3.000 ; 64.00 units/unit
Why: First computation: Ratio=75000/30000=2.500. Second computation: Energy productivity = 8000/150 = 53.33 output units per input unit.
Compute both quantities in order. First: Crop yield is 6.5 t/ha using 450 mm of relevant water supply. Calculate water productivity as kg grain per ha-mm. Second: Crop yield is 4.5 t/ha using 350 mm of relevant water supply. Calculate rainfall-use efficiency as kg grain per ha-mm. Which option gives the two computed results, respectively?
- A. 13.00 kg ha⁻¹ mm⁻¹ ; 12.86 kg ha⁻¹ mm⁻¹
- B. 14.44 kg ha⁻¹ mm⁻¹ ; 12.86 kg ha⁻¹ mm⁻¹ correct
- C. 14.44 kg ha⁻¹ mm⁻¹ ; 11.57 kg ha⁻¹ mm⁻¹
- D. 11.56 kg ha⁻¹ mm⁻¹ ; 9.000 kg ha⁻¹ mm⁻¹
Why: First computation: Water productivity = 6.5×1000/450 = 14.44 kg ha⁻¹ mm⁻¹. Second computation: Rainfall-use efficiency = 4.5×1000/350 = 12.86 kg ha⁻¹ mm⁻¹.
A genotype yields 6, 7, and 8 t/ha in three environments. Calculate mean performance.
- A. 4.900 t/ha
- B. 9.100 t/ha
- C. 6.300 t/ha
- D. 7.000 t/ha correct
Why: Mean=(6+7+8)/3=7.00 t/ha.
Two independent biological yield cases are being compared. Case 1: Grain yield is 4 t/ha and aboveground residue is 5 t/ha. Calculate biological yield. Case 2: Grain yield is 5 t/ha and aboveground residue is 6 t/ha. Calculate biological yield. After computing both results, calculate the absolute difference between them.
- A. 1.800 t/ha
- B. 1.600 t/ha
- C. 2.000 t/ha correct
- D. 2.600 t/ha
Why: Case 1 result: 9.000 t/ha. Case 2 result: 11.00 t/ha. Absolute difference = 2.000 t/ha.
Compute both quantities in order. First: Weed dry weight is 200 g/m² in the untreated check and 100 g/m² in treatment. Calculate weed control efficiency. Second: Weed-free yield is 7.0 t/ha and treatment yield is 5.5 t/ha. Calculate weed index. Which option gives the two computed results, respectively?
- A. 50.00 % ; 21.43 % correct
- B. 60.00 % ; 21.43 %
- C. 50.00 % ; 17.14 %
- D. 45.00 % ; 23.57 %
Why: First computation: WCE = (200−100)/200×100 = 50.00%. Second computation: WI = (7.0−5.5)/7.0×100 = 21.43%.
Two independent generation mean analysis cases are being compared. Case 1: Generation means P₁=50, P₂=70, F₁=68. Calculate F₁ deviation from the mid-parent. Case 2: Generation means P₁=40, P₂=60, F₁=55. Calculate F₁ deviation from the mid-parent. After computing both results, calculate the absolute difference between them.
- A. 3.600 trait units
- B. 3.900 trait units
- C. 3.300 trait units
- D. 3.000 trait units correct
Why: Case 1 result: 8.000 trait units. Case 2 result: 5.000 trait units. Absolute difference = 3.000 trait units.
Compute both quantities in order. First: A phenological phase lasts 40 days. Using development rate = 1/duration, calculate the rate. Second: A recommendation supplies 60 kg nutrient/ha to 2 ha. Calculate total nutrient required. Which option gives the two computed results, respectively?
- A. 0.0175 day⁻¹ ; 120.0 kg nutrient
- B. 0.0250 day⁻¹ ; 96.00 kg nutrient
- C. 0.0250 day⁻¹ ; 120.0 kg nutrient correct
- D. 0.0300 day⁻¹ ; 84.00 kg nutrient
Why: First computation: Development rate = 1/40 = 0.0250 day⁻¹. Second computation: Nutrient required = 60×2 = 120.00 kg.

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Computational Questions — Crop Science Reviewer Questions

Sample Computational Questions questions with answers and explanations

Use HSD=q√(MSE/r), q=4.0, MSE=9, r=4. Calculate Tukey HSD.

A genotype yields 6, 7, and 8 t/ha in three environments. Calculate mean performance.

Compute both quantities in order. First: A phenological phase lasts 40 days. Using development rate = 1/duration, calculate the rate. Second: A recommendation supplies 60 kg nutrient/ha to 2 ha. Calculate total nutrient required. Which option gives the two computed results, respectively?

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